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+l=2.5+1.5//span, in m
+R=0.15//rise, in m
+t=0.25//tread in m
+sigma_cbc=7//in MPa
+sigma_st=275//in MPa
+//assuming 50 mm per 1 m of span
+D=50*l//in mm
+W1=D/10^3*25*1.5*sqrt(R^2+t^2)/t//slab load on plan, in kN/m
+W2=1/2*R*t*1.5*25/t//load of step per metre, in kN/m
+W3=1.5*5//live load, in kN/m
+W=W1+W2+W3//in kN/m
+M=W*l^2/8//in kN-m
+d=sqrt(M*10^6/0.81/1.5/10^3)//in mm
+d=177//in mm
+//assume 10 mm dia bars
+dia=10//in mm
+D=d+dia/2+25//which is slightly more than assumed value, hence OK
+D=200//in mm
+d=D-dia/2-25//in mm
+z=0.92*d//in mm
+Ast=M*10^6/sigma_st/z//in sq mm
+s1=1500*0.785*dia^2/Ast//spacing of 10 mm dia bars, in mm
+s1=130//assume, in mm
+Ads=0.12/100*D*1.5*10^3//distribution steel, in sq mm
+//provide 8 mm dia bars
+s2=1000*0.785*8^2/Ads//in mm
+s2=140//in mm
+//let span-to-depth ratio be 'a'
+a=l*10^3/D
+pt=Ast/1500/D*100//pt=0.3
+//for Fe500 grade steel and pt=.3
+MF=1.2
+b=20*MF//permissible span-to-depth ratio
+//as a<b, hence OK
+mprintf("Summary of design\nSlab thickness=%d mm\nCover = 25 mm\nMain steel = 10 mm dia bars @ %d mm c/c\nDistribution steel = 8 mm dia @ %d mm c/c",D,s1,s2)