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+l=1//span, in m
+t=0.27//tread in m
+sigma_cbc=5//in MPa
+sigma_st=140//in MPa
+MF=1.6
+a=MF*7
+D=l*10^3/a//in mm
+D=100//assume, in mm
+W1=D/10^3*t*25//in kN/m
+M1=W1*l/2//in kN-m
+M2=t*3*l/2//in kN-m
+M3=1.3*l//in kN-m
+M=M1+max(M2,M3)//in kN-m
+d=sqrt(M*10^6/0.87/t/10^3)//in mm
+d=83//in mm
+//assume 8 mm dia bars
+dia=8//in mm
+D=d+dia/2+15//this is slightly more than assumed value, hence OK
+D=100//in mm
+z=0.87*d//in mm
+Ast=M*10^6/sigma_st/z//in sq mm
+n=Ast/0.785/8^2
+n=4//assume
+Ads=0.15/100*D*t*10^3//distribution steel, in sq mm
+//provide 6 mm dia bars
+s=1000*0.785*6^2/Ads//>5d=415 mm
+s=415//in mm
+Tbd=0.6//in MPa
+Ld=dia*sigma_st/4/Tbd//in mm
+Ld=470//assume, in mm
+mprintf("Summary of design\nThickness of steps=%d mm\nCover from top=15 mm\nMain steel = 8 mm dia, %d in each step with development length of %d mm\nDistribution steel = 6 mm dia @ %d mm c/c",D,n,Ld,s)