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+// Exa 6.2
+
+clc;
+clear;
+
+// Given data
+
+/// Referring Fig. 6.5- Adjustable regulator
+Vo= 7.5; // Volts
+
+// Solution
+
+printf(' From the data sheeet of 7805, IQ=4.2 mA. Say, we choose IR1 = 25 mA.\n ');
+IQ = 0.0042; // Amperes
+IR1 = 0.025; //Amperes
+printf(' The voltage across load for 7805 is 5 Volts.\n ');
+VR=5; // Volts
+R1 = VR/IR1;
+printf(' Thus, calculated value of R1 = %d Ω. \n ',R1);
+
+printf(' We have to choose R2 as to develop a voltage of 2.5 V across it. So, R2 comes out to be,\n ');
+R2= 2.5/(IR1+IQ);
+printf(' The value of R2 = %d Ω. \n ',int(R2));