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+// Exa 5.4
+
+clc;
+clear;
+
+// Given data
+
+// Phase shift oscillator as given in Fig. 5.15
+
+F=100; // Oscillation frequency(Hz)
+
+
+// Solution
+
+printf(' Let C=0.1 microFarads, then from Eq. (5.25) we can get value of R. \n ');
+R = 1/(sqrt(6)*2*%pi*10^-7*F);
+
+printf(' The value of R as calculated = %.2f kΩ. \n ',R/1000);
+
+printf(' To prevent overloading of the amplifier by RC network, R1 <= 10*R. \n');
+R1=10*R;
+printf(' Therefore R1 = %d kΩ. \n ',round(R1/1000));
+// Since Rf = 29*R1;
+Rf= 29*round(R1/1000); // kΩ
+printf(' Since Rf = 29*R1, therefore value of Rf = %d kΩ. \n ',Rf);