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+// Exa 3.1
+
+clc;
+clear;
+
+// Given data
+
+//Fig. 3.1(e) shows an inverting amplifier
+ACL = -10; // open loop gain of ap-amp 741
+R1 = 10*10^6; // Input impedence in Ω
+
+// Solution
+
+printf(' In fig. 3.1(e), to set input impedence Ri = 10 MΩ , pick R1 = 10 MΩ. ');
+// since, ACL = - Rf/R1;
+// Therefore,
+Rf = -ACL*R1;
+printf('\n  The calculated value of Rf = %d MΩ. \n ',Rf/10^6);
+printf(' Choose Rt = 47 kΩ. \n ');
+Rt = 47*10^3; // Ω
+Rs = (Rt^2)/(Rf-2*Rt);
+printf(' Calculated Rs = %d Ω. ',Rs);