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+// Exa 2.4
+
+clc;
+clear;
+
+// Given data
+
+// Referring circuit given in Fig. 2.7(a)
+R1= 5*10^3; // Ω
+Rf=20*10^3; // Ω
+Vi=1; // Input voltage(V)
+RL=5*10^3; // Load resistor(Ω)
+
+
+// Solution
+
+Vo= (1+(Rf/R1))*Vi; // Output voltage(V)
+printf('The output voltage i.e vo = %d V. \n',Vo);
+AcL=Vo/Vi; // Closed loop Gain
+printf(' The closed loop gain i.e Acl = %d. \n',AcL);
+IL=Vo/RL; // Output current(A)
+printf(' The load current i.e iL = %d mA. \n',IL*1000);
+I1=Vi/R1; // Input current(A)
+Io=IL+I1; // Total current(A)
+printf(' The output current i.e io = %.2f mA. \n',Io*1000);
+disp("The op-amp output current Io flows outwards from the output junction.");