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+// Exa 2.14
+
+clc;
+clear;
+
+// Given data
+
+// Fig. 2.25 shows circuit for current example
+Vo = 6; // Volts
+B = 200;
+R1 =15; // kΩ
+R2 = 2.8; // kΩ
+Vcc = 12; // volts
+Vbe = 0.7; // Volts
+
+// Solution
+
+Iref = (Vcc-Vbe)/R1;
+I1 = Vbe/R2;
+
+// At node A- Iref = Ic1 + 2IB + I1;
+ //           Iref = Ic1*(1+2/B)+I1;
+  // Therefore; we get Ic1 as-
+Ic1 = (Iref-I1)/(1+2/B);
+printf(' The value of Ic1 = %.3f mA.\n',Ic1 );
+printf('  The value of Ic2 = Ic1 due to mirror effect.');
+ // by KVL to outer loop we get Rc value
+ // 12V = Ic2*Rc +Vo;
+Rc = (Vcc-Vo)/Ic1;
+printf('\n  The value of Rc = %d kΩ. \n',Rc);