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+// Calculating the armature voltage drop
+clc;
+disp('Example 9.12, Page No. = 9.49')
+// Given Data
+P = 300;// Power rating (in kW)
+V = 500;// Voltage rating (in volts)
+a = 6;// Number of parallel paths (Since lap winding)
+p = 0.021;// resistivity (in ohm mm square)
+Ns = 150;// Number of slots
+Lmt = 2.5;// Length of mean turn (in meter)
+az = 25;// Area of each conductror (in mm square)
+// Calculation of the armature voltage drop
+Z = Ns*8;// Number of armature conductors. Since 8 conductors per slot
+ra = Z*p*Lmt/(2*a*a*az);// Resistance of armature (in ohm)
+Ia = P*10^(3)/V;// Armature current
+disp(Ia*ra,'Armature voltage drop (Volts) =');
+//in book answer is 21 (Volt). The answers vary due to round off error