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+// Calculating the net iron area and window area and full load mmf
+clc;
+disp('Example 5.6, Page No. = 5.80')
+// Given Data
+Q = 400;// kVA rating
+R = 2.4*10^(-6);// Ratio of flux to full load mmf
+f = 50;// Frequency (in Hz)
+Bm = 1.3;// Maximum flux density of core (in Wb per meter square)
+Kw = 0.26;// Window space factor
+s = 2.7;// Current density (in Ampere per mm square)
+// Calculation of the net iron area
+K = (4.44*f*R*10^(3))^(1/2);
+Et = K*Q^(1/2);// Voltage per turn (in Volts)
+Flux = Et/(4.44*f);// Flux (in Wb)
+Ai = Flux/Bm;// Net iron area (in meter square)
+disp(Ai,'Net iron area (meter square)=');
+// Calculation of the net window area
+Aw = Q/(2.22*f*Bm*Kw*s*10^(6)*Ai*10^(-3));// Window area (in meter square)
+disp(Aw,'Window area (meter square)=');
+// Calculation of the full load mmf
+AT = Flux/R;// Full load mmf (in A)
+disp(AT,'Full load mmf (A)=');
+//in book answers are 0.0507 (meter square), 0.0777 (meter square) and 27500 (A) respectively.  The answers vary due to round off error