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Diffstat (limited to '3681/CH5/EX5.13')
| -rw-r--r-- | 3681/CH5/EX5.13/Ans5_13.PNG | bin | 0 -> 6455 bytes | |||
| -rw-r--r-- | 3681/CH5/EX5.13/Ex5_13.sce | 21 |
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diff --git a/3681/CH5/EX5.13/Ans5_13.PNG b/3681/CH5/EX5.13/Ans5_13.PNG Binary files differnew file mode 100644 index 000000000..9e6f37822 --- /dev/null +++ b/3681/CH5/EX5.13/Ans5_13.PNG diff --git a/3681/CH5/EX5.13/Ex5_13.sce b/3681/CH5/EX5.13/Ex5_13.sce new file mode 100644 index 000000000..601315a10 --- /dev/null +++ b/3681/CH5/EX5.13/Ex5_13.sce @@ -0,0 +1,21 @@ +// Calculating the leakage reactance of the transformer referred to the h.v. side
+clc;
+disp('Example 5.13, Page No. = 5.89')
+// Given Data
+// 6600/400 V, delta/star 3-phase core type transformer
+Q = 300;// kVA rating
+f = 50;// Frequency (in Hz)
+u0 = 4*%pi*10^(-7);
+Tp = 830;// h.v winding turns
+Lmt = 0.9;// Length of mean turn (in meter)
+Lc = 0.5;// Height of coils (in meter)
+a = 0.015;// Width of duct between h.v and l.v. windings (in meter)
+bp = 0.025;// Width of h.v. winding (in meter)
+bs = 0.016;// Width of l.v. winding (in meter)
+// Calculation of the leakage reactance of the transformer referred to the h.v. side
+Xp = 2*%pi*f*u0*Tp*Tp*Lmt/Lc*(a+(bp+bs)/3);// Leakage reactance referred to the primary side (ohm)
+disp(Xp,'(a) Leakage reactance referred to the primary side (ohm)=');
+// If the l.v. winding divided into two parts, one on each side of h.v. winding
+Xp = %pi*f*u0*Tp*Tp*Lmt/Lc*(a+(bp+bs)/6);// Leakage reactance referred to the primary side (ohm)
+disp(Xp,'(b) Leakage reactance referred to the primary side (ohm)=');
+//in book answers are 14 ohm and 5.36 ohm respectively. The answers vary due to round off error
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