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Diffstat (limited to '3681/CH4/EX4.25')
| -rw-r--r-- | 3681/CH4/EX4.25/Ans4_25.PNG | bin | 0 -> 6372 bytes | |||
| -rw-r--r-- | 3681/CH4/EX4.25/Ex4_25.sce | 17 |
2 files changed, 17 insertions, 0 deletions
diff --git a/3681/CH4/EX4.25/Ans4_25.PNG b/3681/CH4/EX4.25/Ans4_25.PNG Binary files differnew file mode 100644 index 000000000..5f3242dd7 --- /dev/null +++ b/3681/CH4/EX4.25/Ans4_25.PNG diff --git a/3681/CH4/EX4.25/Ex4_25.sce b/3681/CH4/EX4.25/Ex4_25.sce new file mode 100644 index 000000000..01d892fdf --- /dev/null +++ b/3681/CH4/EX4.25/Ex4_25.sce @@ -0,0 +1,17 @@ +// Calculating the amount of oil and amount of water
+clc;
+disp('Example 4.25, Page No. = 4.51')
+// Given Data
+MVA = 40;// MVA rating of transformer
+Q = 200;// Total losses (in kW)
+Q_oil = 0.8*Q;// Since 20% of losses are dissipated by tank walls Heat taken up by oil (in kW)
+// Calculation of the amount of oil
+T = 20;// Temperature rise of oil (in degree celsius)
+cp = 0.4;// by assuming
+Vo = 0.24*Q_oil/(cp*T);// Amount of oil (in litre per second)
+disp(Vo,'Amount of oil (litre per second)=');
+// Calculation of the amount of water
+T = 10;// Temperature rise of water (in degree celsius)
+Vw = 0.24*Q_oil/T;// Amount of water (in litre per second)
+disp(Vw,'Amount of water (litre per second)=');
+//in book Vo is equal to 4.8 (litre per second) and Vw is equal to 3.84 (litre per second). The answers vary due to round off error
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