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Diffstat (limited to '3681/CH4/EX4.2/Ex4_2.sce')
| -rw-r--r-- | 3681/CH4/EX4.2/Ex4_2.sce | 17 |
1 files changed, 17 insertions, 0 deletions
diff --git a/3681/CH4/EX4.2/Ex4_2.sce b/3681/CH4/EX4.2/Ex4_2.sce new file mode 100644 index 000000000..45f094c79 --- /dev/null +++ b/3681/CH4/EX4.2/Ex4_2.sce @@ -0,0 +1,17 @@ +// Calculating the loss that will be conducted across the the laminations
+clc;
+disp('Example 4.2, Page No. = 4.3')
+// Given Data
+Q_con_5 = 25;// Heat Dissipated
+t_5 = 20;// Thickness of laminations in mm
+S_5 = 2500;// Cross-section area of conduction in mm square
+T_5 = 5;// Temperature difference in degree celsius
+t_20 = 40;// Thickness of laminations in mm
+S_20 = 6000;// Cross-section area of conduction in mm square
+T_20 = 20;// Temperature difference in degree celsius
+// Calculation of heat conducted across the laminations
+p_along = (T_5*S_5*10^(-6))/(Q_con_5*t_5*10^(-3));// Thermal resistivity along the direction of laminations
+p_across = 20*p_along;// Thermal resistivity across the direction of laminations
+Q_con_20 = S_20*10^(-6)*T_20/(p_across*t_20*10^(-3));// Heat conducted across the the laminations
+disp(Q_con_20,'Heat conducted across the the laminations(W)=');
+//in book answer is 6 W. The answers vary due to round off error
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