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+// Example 9.2
+// Computation for VCEQ and re' for case(a),o/p overall gain, gain,i/p resistance, overall current gain & o/p resistance for case(b),minimum value of Ce for case(c)//
+// Page no.370
+
+clc;
+clear;
+close;
+
+//Given data
+hFE=100;
+hfe=150;
+Rc_A=2.2*10^3;
+VBB=2.79;
+VBEQ=0.7;
+Rb=7.67*10^3;
+Re1=0;
+Re2=2.2*10^3;
+VCC=12;
+Rc_B=0;
+RL=47*10^3;
+R1=33*10^3;
+R2=10*10^3;
+Rs=600;
+fs_min=1000;
+
+//..................................(A).....................................//
+
+//Calculation for collector current//
+//for Re2=0:
+ICQ=hFE*((VBB-VBEQ)/(Rb+(hFE*(Re1+Re2))));
+
+//Calculation for quiescent collector to emitter voltage//
+VCEQ=VCC-ICQ*Re2;
+
+//Calculation for re_dash//
+re_dash=(26*10^-3)/ICQ;//IEQ=ICQ
+
+//...................................(B)....................................//
+
+//Calculation for resistance of the parallel combination of Rc and Rl1//
+Rl2e=(Re2*RL)/(Re2+RL);
+
+//Calculation for Rth//
+Rth=1/((1/Rs)+(1/R1)+(1/R2));
+
+//Calculation for overall voltage gain of the amplifier//
+Av2s=((hfe*Rl2e)/(Rth+hfe*(re_dash+Rl2e)))*(((R1*R2)/(R1+R2))/(Rs+(R1*R2)/(R1+R2)));
+
+//Calculation for input resistance at the base//
+Rin_base=hfe*re_dash;
+
+//Calculation for total input resistance//
+Rin_total=((1/R1)+(1/R2)+(1/Rin_base))^-1;
+
+//Calculation for overall current gain//
+AIs=((hfe*(Rs+Rin_total))/(Rth+(hfe*(re_dash+Rl2e))))*(((R1*R2)/(R1+R2))/(Rs+(R1*R2)/(R1+R2)));
+
+//Calculation for output resistance//
+Rout=Re2*(Rth+hfe*re_dash)/(Rth+hfe*(re_dash+Re2));
+
+//...................................(C)....................................//
+
+//Calculation for the minimum value Ce1_min of the coupling capacitor Ce//
+Ce_min=1.59/(fs_min*(Rout+RL));
+
+//Displaying the result in command window
+printf("\n ......................(A)............................");
+printf('\n Collector current = ICQ = %0.2f mA',ICQ*10^3);
+printf('\n Quiescent collector to emitter voltage = VCEQ = %0.2f V',VCEQ);
+printf('\n Value of re_dash = %0.2f K',re_dash);
+printf("\n \n ......................(B)............................");
+printf('\n Overall voltage gain of the amplifier = %0.2f ',Av2s);
+printf('\n Rl2e = %0.1f K',Rl2e*10^-3);
+printf('\n Rth = %0.0f ohm',Rth);
+printf('\n Input resistance at the base = %0.2f K',Rin_base*10^-3);
+printf('\n Total input resistance = %0.2f K',Rin_total*10^-3);
+printf('\n Overall current gain = AIs = %0.2f ',AIs);
+printf('\n Output resistance = Rout = %0.1f ohm',Rout);
+printf("\n \n ......................(C)............................");
+printf('\n The minimum value Ce1_min of the coupling capacitor Ce = %0.1f nF',Ce_min*10^9);
+
+//Answers are varying due to round off error//