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-rw-r--r--3655/CH2/EX2.2/Ex2_2.pngbin0 -> 54432 bytes
-rw-r--r--3655/CH2/EX2.2/Ex2_2.sce35
-rw-r--r--3655/CH2/EX2.3/Ex2_3.pngbin0 -> 48286 bytes
-rw-r--r--3655/CH2/EX2.3/Ex2_3.sce32
-rw-r--r--3655/CH2/EX2.4/Ex2_4.pngbin0 -> 50533 bytes
-rw-r--r--3655/CH2/EX2.4/Ex2_4.sce43
-rw-r--r--3655/CH2/EX2.5/Ex2_5.pngbin0 -> 52319 bytes
-rw-r--r--3655/CH2/EX2.5/Ex2_5.sce31
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diff --git a/3655/CH2/EX2.2/Ex2_2.png b/3655/CH2/EX2.2/Ex2_2.png
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diff --git a/3655/CH2/EX2.2/Ex2_2.sce b/3655/CH2/EX2.2/Ex2_2.sce
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+// Example 2.2
+//computation of wavelenth of second emitted photon//
+// Page no. 45
+
+clc;
+clear;
+close;
+
+//Given data
+lambdaA=1400;//wavelength of absorbed photon//
+lambdaB=1850;//wavelength of first emitted photon//
+
+//Calculation for total energy of absorbed photon//
+E=(12400/lambdaA);
+
+//Calculation for energy of emitted photon of wavelenth lambdaB//
+E1=(12400/lambdaB);
+
+//Calculation for energy of second emitted photon//
+E2=E-E1;
+
+//Calculation for wavelenth of second emitted photon//
+lambda2=(12400/E2);
+
+//Displaying the result in command window
+printf('\n Total energy of absorbed photon in eV = %0.3f eV',E);
+printf('\n \n Energy of emitted photon of wavelength 1850 A = %0.3f eV',E1);
+printf('\n \n Energy of the second emitted photon= %0.3f eV',E2);
+printf('\n \n Wavelenth of second emitted photon = %0.0f A',lambda2);
+
+//The answers vary due to roundoff error//
+
+
+
+
diff --git a/3655/CH2/EX2.3/Ex2_3.png b/3655/CH2/EX2.3/Ex2_3.png
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diff --git a/3655/CH2/EX2.3/Ex2_3.sce b/3655/CH2/EX2.3/Ex2_3.sce
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+// Example 2.3
+//computation of number of photons per second emitted by lamp//
+// Page no. 46
+
+clc;
+clear;
+close;
+
+//Given data
+lambda=2537;//wavelength of absorbed photon//
+
+
+//Calculation for total energy of absorbed photon//
+E=(12400/lambda);
+
+//Calculation for radiated power//
+P_radiated=(0.05/(1.60*10^-19));
+
+//Calculation for number of photons per second//
+photon=(P_radiated/E);
+
+//Displaying the result in command window
+printf('\n Total energy per photon = %0.2f eV/photon',E);
+printf('\n \n Radiated Power = %0.2f x 10^17 eV/sec',P_radiated*10^-17);
+printf('\n \n The number of photons per second = %0.2f x 10^16 photons/second',photon*10^-16);
+
+//The answers vary due to roundoff error//
+
+
+
+
+
diff --git a/3655/CH2/EX2.4/Ex2_4.png b/3655/CH2/EX2.4/Ex2_4.png
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diff --git a/3655/CH2/EX2.4/Ex2_4.sce b/3655/CH2/EX2.4/Ex2_4.sce
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+// Example 2.4
+//computation of (A) minimum speed of electron travelling (B) minimum frequency of photon//
+// Page no. 47
+
+clc;
+clear;
+close;
+
+//Given data
+ip=21.5;//ionization potential of neon
+e=1.602*10^-19;
+m=9.109*10^-31;
+v_freespace=2.998*10^8;//velocity of light in free space
+planck_const=6.63*10^-34;
+
+
+//..................................(A)......................................//
+
+//Calculation for velocity of the electron//
+v=sqrt((2*ip*e)/m);
+
+//..................................(B)......................................//
+
+//Calculation for wavelength of a photon with energy equal to the ionization potential//
+lambda=12400/ip;
+
+//Calculation for frequency of the photon//
+f=v_freespace/(lambda*10^-10);
+
+//Calculation for frequency of the photon using alternate method//
+f1=(ip*e)/planck_const;
+
+
+//Displaying the result in command window
+printf('\n Velocity of the electron = %0.2f x 10^6 m/sec',v*10^-6);
+printf('\n \n Wavelength of a photon with energy equal to the ionization potential = %0.2f A',lambda);
+printf('\n \n Frequency of the photon = %0.1f x 10^15 Hz',f*10^-15);
+
+
+
+
+
+
diff --git a/3655/CH2/EX2.5/Ex2_5.png b/3655/CH2/EX2.5/Ex2_5.png
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diff --git a/3655/CH2/EX2.5/Ex2_5.sce b/3655/CH2/EX2.5/Ex2_5.sce
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+// Example 2.5
+//computation of the energy in jules of the impinging electron after the collision//
+// Page no. 49
+
+clc;
+clear;
+close;
+
+//Given data
+e=1.602*10^-19;
+
+
+//Calculation for the Kinetic energy E1 gained by the electron//
+E1=10*e;
+
+//Calculation for the Kinetic energy E2 needed to be transferred fom the bombarded electron to the atom//
+E2=3.07*e;//(7.73eV-4.66eV)=3.07eV
+
+//Calculation for the Kinetic energy E of the electron after the collision//
+E=E1-E2;
+
+
+//Displaying the result in command window
+printf('\n Kinetic energy E1 gained by the electron = %0.2f x 10^-19 J',E1*10^19);
+printf('\n \n Kinetic energy E2 needed to be transferred fom the bombarded electron to the atom = %0.2f x 10^-19 J',E2*10^19);
+printf('\n \n Kinetic energy E of the electron after the collision = %0.2f x 10^-19 J',E*10^19);
+
+
+
+
+