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+//Solutions to Problems In applied mechanics
+//A N Gobby
+clear all;
+//mass moment of inertia, kinetic enrgy and shear blades
+clc
+//initialisation of variables
+w=2//tonf
+t=250//rev/min
+g=32.2//ft
+h=2240//ft
+f=0.8//percent
+t1=60//ft
+s=1*(2/3)//min
+r=480//ft
+w1=20//ft
+//CALCULATIONS
+M=(w*h*(w^2))/g//slug ft^2
+A=(t*(w*%pi/t1))/t1*s//rad/s^2
+I=M*A//lbf ft
+K=1/2*(M)*(2*%pi/t1)^2*r*w1//ft lbf
+F=f*K/(3/12)//lbf
+//RESULTS
+printf('the mass moment of inertia =% f lbf ft',I)
+printf('the kinetic energy=% f ft lbf',K)
+printf('the average force on the shear blades=% f lbf',F)