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+clc;
+clear;
+Na=10^17 //in cm^-3
+epsilon_0=8.85*10^-14 //in F/cm
+Emax=5*10^5 //peak electric field in V/cm
+e=1.6*10^-19 //in J
+epsilon_si=88.76*10^-14 //in F/cm
+
+//Calculation
+E=(Emax*Emax*epsilon_si)/(e*Na)
+
+mprintf("Breakdown voltage= %2.2f V",E) //The answers vary due to round off error