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+clc;
+//ex2.7
+//assume diode is ideal(Vf=0V)
+Vs=10; //Volt
+Rt=3030; //Ohm
+IT=Vs/Rt; //Ampere
+//assume diode is practical(Vf=0.7V)
+Vf=1.4; //Volt
+Vs1=Vs-Vf; //Volt
+IT1=Vs1/Rt; //Ampere
+e=(-100*(IT1-IT))/IT1; //Percentage of error between two circuit current
+disp( 'Ampere',IT*1,"IT=");
+disp( 'Ampere',IT1*1,"IT1=");
+disp( '%',e*1,"Percentage Error="); //The answers vary due to round off error
+