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+
+clc
+//given
+ne=31
+na=25
+nb=90
+nc=83
+Ta=10 //lbft
+//Ne-Nf/(Nc-Nf)=-83/31
+k=114/83//k=Nc/Nf As Ne = 0, on simplification we get Nc/Nf= 114/83
+j=-90/25//j=Na/Nb
+//Nc=Nb, Thus Na/Nc=-90/25
+//Na/Nf=(Na/Nc)*(Nc/Nf) ie Na/Nf=k*j
+//Tf*Nf=Ta*Na
+Tf=Ta*k*j
+printf("\nTorque exerted on driven shaft = %.1f lb.ft\n",Tf)