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Diffstat (limited to '3588/CH4/EX4.4/EX4_4.sce')
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diff --git a/3588/CH4/EX4.4/EX4_4.sce b/3588/CH4/EX4.4/EX4_4.sce new file mode 100644 index 000000000..39f3c563c --- /dev/null +++ b/3588/CH4/EX4.4/EX4_4.sce @@ -0,0 +1,48 @@ +//Clearing console +clc +clear + +//Intializing Variables +b = 1 +h = 1 +A = 1 +L = 20 +I = (b*h^3)/12 +E = 10*10^6 +M = 90 + +//Calculating elemental stiffness matrices +k1([2,3,5,6],1:6) = ((E*I)/(L^3))*[0 12 6*L 0 -12 6*L;0 6*L 4*(L)^2 0 -6*L 2*(L)^2;0 -12 -6*L 0 12 -6*L;0 6*L 2*(L)^2 0 -6*L 4*(L)^2] +k1([1,4],1:6) = (A*E/L)*[1 0 0 -1 0 0;-1 0 0 1 0 0] +k2 = k1 //as L1 = L2 and both are of same material (E1 = E2) + +//Calculating transformation matrix +R = [cosd(M) sind(M) 0 0 0 0;-sind(M) cosd(M) 0 0 0 0;0 0 1 0 0 0;0 0 0 cosd(M) sind(M) 0;0 0 0 -sind(M) cosd(M) 0;0 0 0 0 0 1] + +//Constructing elemental Stiffness matrix in global system +K1 = (R)'*k1*R + +//Constructing Global Stiffness matrix +K(1,[1:9])= [K1(1,[1:6]) 0 0 0] +K(2,[1:9])= [K1(2,[1:6]) 0 0 0] +K(3,[1:9])= [K1(3,[1:6]) 0 0 0] +K(4,[1:9])= [K1(4,[1:3]) K1(4,4)+k2(1,1) K1(4,5)+k2(1,2) K1(4,6)+k2(1,3) k2(1,[4:6])] +K(5,[1:9])= [K1(5,[1:3]) K1(5,4)+k2(2,1) K1(5,5)+k2(2,2) K1(5,6)+k2(2,3) k2(2,[4:6])] +K(6,[1:9])= [K1(6,[1:3]) K1(6,4)+k2(3,1) K1(6,5)+k2(3,2) K1(6,6)+k2(3,3) k2(3,[4:6])] +K(7,[1:9])= [0 0 0 k2(4,[1:6])] +K(8,[1:9])= [0 0 0 k2(5,[1:6])] +K(9,[1:9])= [0 0 0 k2(6,[1:6])] + +//Constructing Force matrix (required values) +F([4:6],1) = [0;-100;-333.3] +U([1:3],1) =[0; 0; 0] + +//Solving for displacements +U(4:6,1)=linsolve(K(4:6,4:6),-F(4:6,1)) //K*U=F (equlibrium equation) + +//Solving for local displacements +u(1:6,1) = R*U(1:6,1) + +//Printing Results +printf('\nResults\n') +printf('\nNode-B Displacement Components \nUx=%fin \nUy=%fin \nTheta=%frad',u(4,1),u(5,1),u(6,1)) |