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+// Exa 15.7
+
+clc;
+clear all;
+
+// Given data
+// Refering fig. 15.20- Wide band reject filter
+
+Fl=100;// Hz
+Fh=1000;// Hz
+
+// Solution
+// 1. For a high pass filter Fh=1 KHz =1/(2*%pi*R*C);
+disp(" For a high pass filter section");
+disp(" Let C1=0.01 micro farads ");
+C1=0.01;// micro farads
+R1=1/(2*%pi*Fh*C1*10^-6);
+printf('  The value of resistor = %.1f k Ohms \n',R1/1000);
+
+// 2. For a low pass filter Fl=100 Hz=1/(2*%pi*R*C);
+disp(" For a low pass filter section");
+disp(" Let C2=0.01 micro farads ");
+C2=0.01;// micro farads
+R2=1/(2*%pi*Fl*C2*10^-6);
+printf('  The value of resistor = %.1f k Ohms \n',R2/1000);
+
+disp(" Since the pass band gain is 4, the gain of the high pass and low pass filter sections are set each equal to 2. Therefore, R1=Rf=10 k Ohmss for both section");
+disp(" Further, the gain of the summing amplifier is set to 1, therefore R2=R3=R4=10 k Ohms"); // K ohms
+R=10000;//Ohms(R=R2=R3=R4)
+Rom=(1/R+1/R+1/R)^-1;
+printf('  The value of Rom = %.1f k Ohms\n',Rom/1000);
+// There is a printing mistake as c=0.1 micro fard is printed instead of 0.01 micro farad.