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+// Exa 15.5
+
+clc;
+clear all;
+
+// Given data
+
+Fl=100;// lower cutoff frequency in Hz
+Fh=1000;// higher cutoff frequency in Hz
+Af=4;// pass band gain
+
+// Solution
+
+// Wide bandpass filter design
+// 1. For a low pass filter Fh=1 KHz =1/(2*%pi*R*C);
+
+disp(" For a low pass filter section");
+disp(" Let C1=0.01 micro farads ");
+C1=0.01;// micro farads
+R1=1/(2*%pi*Fh*C1*10^-6);
+printf('The value of resistor = %.1f K ohms \n',R1/1000);
+
+// 2. For a high pass filter Fl=100 Hz=1/(2*%pi*R*C);
+disp(" For a high pass filter section");
+disp(" Let C2=0.01 micro farads ");
+C2=0.01;// micro farads
+R2=1/(2*%pi*Fl*C2*10^-6);
+printf(' The value of resistor = %d K ohms \n',R2/1000);
+
+disp(" Since the pass band gain is 4, the gain of the high pass and low pass filter sections are set each equal to 2. Therefore, R1=Rf=10 K ohms for both sections.");
+
+// Q for filter
+Fc=sqrt(Fl*Fh);
+
+Q=Fc/(Fh-Fl);
+printf(' The value of Q =%.2f which is less than 10, as expected for a wide band pass filter\n',Q);