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+// Exa 15.3
+
+clc;
+clear all;
+
+// Given data
+
+Fh= 2*10^3;// Cutoff frequency in Hz
+	
+// Solution
+
+disp(" Let C2=C3=0.0033 micro farads ");
+
+// Fh=1/(2*%pi*R*C); where R=R2=R3 and C2=C3=C;
+C=0.0033*10^-6; // farads
+// Therefore
+R=1/(2*%pi*Fh*C);
+printf('  Calculated value of R = %.1f K ohms. Let, R=R2=R3=22 k Ohms is selected\n',R/1000);
+// Since Rf/R1=0.586, therefore Rf=0.586*R1;
+// Let fix value of R1 as
+R1=10*10^3; // Ohms
+Rf=0.586*R1;
+printf('  The remaining components after calculation comes out to be as Rf= %.2f k Ohms and R1= %d k Ohms \n',Rf/1000,R1/1000);