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+// Exa 11.5
+
+clc;
+clear all;
+
+// Given data
+// Refering circuit in Fig. 11.15(a) and graph in 11.15(b) on page no.317
+
+R1=5; // k Ohms
+R2=5; //k Ohms
+R3= 5; // k Ohms
+E=6; // Applied voltage(V)
+
+// Solution
+
+// The value of Rv when bridge is balanced is calculated as
+Rv=R2*R3/R1;
+printf(' The value of Rv = %d K Ohms \n' , Rv);
+disp(" From the graph, the temperature at which bridge is balanced is = 80      degree celsius");
+disp(" From the graph, the resistance Rv for balancing bridge at 60 degree celcius comes out to be 4.5 k Ohms ");
+// Therefore
+Rv1=4.5; // Resistance Rv at 60 degree celcius(K ohms)
+es=E*(R3/(R1+R3) - Rv1/(R2+Rv1) ); // Error signal
+printf(' The amplitude of error signal at 60 degree celsius is = %.3f V \n',es);