diff options
Diffstat (limited to '3542/CH7')
| -rw-r--r-- | 3542/CH7/EX7.3/7_3.jpg | bin | 0 -> 70438 bytes | |||
| -rw-r--r-- | 3542/CH7/EX7.3/Ex7_3.sce | 29 | ||||
| -rw-r--r-- | 3542/CH7/EX7.4/7_4.jpg | bin | 0 -> 79569 bytes | |||
| -rw-r--r-- | 3542/CH7/EX7.4/Ex7_4.sce | 25 |
4 files changed, 54 insertions, 0 deletions
diff --git a/3542/CH7/EX7.3/7_3.jpg b/3542/CH7/EX7.3/7_3.jpg Binary files differnew file mode 100644 index 000000000..8bf4e52e6 --- /dev/null +++ b/3542/CH7/EX7.3/7_3.jpg diff --git a/3542/CH7/EX7.3/Ex7_3.sce b/3542/CH7/EX7.3/Ex7_3.sce new file mode 100644 index 000000000..b2c673e7b --- /dev/null +++ b/3542/CH7/EX7.3/Ex7_3.sce @@ -0,0 +1,29 @@ +// Example no 7.3
+// To determine a)the maximum Doppler shift b)the coherence time of the channel c)the maximum number of symbolsthat could be transmitted
+// Page no. 373
+
+clc;
+clear all;
+
+//Given data
+f=900*10^6; // Carrier frequency in Hz
+c=3*10^8; // Speed of ligth in air (m/s)
+v=80; // Velocity of mobile in km/hr
+v=v*(5/18); // Velocity of mobile in m/s
+lambda=c/f; // Carrier wavelength in meter
+
+// a)To determine the maximum Doppler shift
+fd=v/lambda; // The maximum Doppler shift in Hz
+
+// b)To determine the coherence time of the channel
+Tc=sqrt(9/(16*%pi*fd^2)); // The coherence time of the channel
+// Answer is varrying due to round-off error
+
+// c)To determine the maximum number of symbols that could be transmitted with symbol rate 24.3 ksymbols/sec
+Rs=24.3*10^3; // Symbol rate in symbols/sec
+Nb=Tc*Rs; // The maximum number of transmitted symbols
+
+// Displaying the result in command window
+printf('\n The maximum Doppler shift = %0.2f Hz',fd);
+printf('\n The coherence time of the channel = %0.2f ms',Tc*10^3);
+printf('\n The maximum number of symbols that could be transmitted with symbol rate 24.3 ksymbols/sec = %0.0f symbols',Nb);
diff --git a/3542/CH7/EX7.4/7_4.jpg b/3542/CH7/EX7.4/7_4.jpg Binary files differnew file mode 100644 index 000000000..0ba6f78f6 --- /dev/null +++ b/3542/CH7/EX7.4/7_4.jpg diff --git a/3542/CH7/EX7.4/Ex7_4.sce b/3542/CH7/EX7.4/Ex7_4.sce new file mode 100644 index 000000000..68af60af1 --- /dev/null +++ b/3542/CH7/EX7.4/Ex7_4.sce @@ -0,0 +1,25 @@ +// Example no 7.4
+// To determine probability that the SNR will drop below threshold SNR
+// Page no. 383
+
+clc;
+clear all;
+
+// Given data
+M1=4; // Number of branch diversity
+M2=1; // Number of branch diversity
+gamm=10; // Specified SNR threshold in dB
+gamm=10^(gamm/10); // Specified SNR threshold
+Gamma=20; // Average SNR in dB
+Gamma=10^(Gamma/10); // Average SNR
+
+// Probability that the SNR will drop below 10dB when 4 branch diversity is used
+P4=(1-exp(-gamm/Gamma))^M1; // Probability that the SNR will drop below 10dB
+
+// Probability that the SNR will drop below 10dB when single branch diversity is used
+P1=(1-exp(-gamm/Gamma))^M2; // Probability that the SNR will drop below 10dB
+
+// Displaying the result in command window
+printf('\n Probability that the SNR will drop below 10dB when 4 branch diversity is used = %0.6f',P4);
+printf('\n Probability that the SNR will drop below 10dB when single branch diversity is used = %0.3f',P1);
+printf('\n \n From above results, it is observed that without diversity the SNR drops below the specified threshold with a probability that is three orders of magnitude greater \n than if four branch diversity is used.')
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