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+// Example 3.2
+// To find frequency reuse factor for path loss exponent (n) a)n=4 b)n=3
+// Page No.72
+
+clc;
+clear;
+
+// Given data
+SIdB=15;                     // Signal to interference(dB)
+io=6;                        // Number of cochannel cell
+
+// For n=4
+n1=4;                        // Path loss exponent
+N1=7;                        // First consideration: frequency reuse factor N=7
+DR1=sqrt(3*N1);              // Co-channel reuse ratio
+si1=(1/io)*(DR1)^n1;         // Signal to interference
+sidB1=10*log10(si1);         // Signal to interference(dB)
+
+// For n=3
+n2=3;                        // Path loss exmponent
+si=(1/io)*(DR1)^n2;          // Signal to interference for first consideration: frequency reuse factor N=7
+sidB=10*log10(si);           // Signal to interference(dB)
+
+N2=12;                       // second consideration : frequency reuse factor N=12 since sidB<SIdB 
+DR2=sqrt(3*N2);              // Co-channel reuse ratio
+si2=(1/io)*(DR2)^n2;         // Signal to interference
+sidB2=10*log10(si2);         // Signal to interference(dB)
+
+// Displaying the result in command window
+printf('\n Signal to noise ratio for n=4 with frequency reuse factor N=7 = %0.2f dB',sidB1);
+printf('\n Signal to noise ratio for n=3 with frequency reuse factor N=7 = %0.2f dB',sidB);
+printf('\n Signal to noise ratio for n=3 with frequency reuse factor N=12 = %0.2f dB',sidB2);
+printf('\n Since SIR is for n=3 with frequency reuse factor N=7 greater than the minimum required, so N=12 is used.');