8 files changed, 152 insertions, 0 deletions
diff --git a/3532/CH2/EX2.10/Ex2_10.sce b/3532/CH2/EX2.10/Ex2_10.sce
new file mode 100644
index 000000000..26547987e
--- /dev/null
+++ b/3532/CH2/EX2.10/Ex2_10.sce
@@ -0,0 +1,22 @@
+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 2.5.2\n')
+//given data
+G=0.83*10^11//rigidity modulus in N/m^2
+J=14.7 //mass moment of inertia in kg-m^2
+l1=0.6 //lenght of section 1 in m
+l2=1.8 //lenght of section 2 in m
+l3=0.25 //lenght of section 3 in m
+d1=0.05 //dia of section 1 in m
+d2=0.08 //dia of section 2 in m
+d3=0.03 //dia of section 3 in m
+//calculations
+Kt1=(G/l1)*(%pi/32)*d1^4 //(%pi/32)*d^4 is the section modulus
+Kt2=(G/l2)*(%pi/32)*d2^4
+Kt3=(G/l3)*(%pi/32)*d3^4
+Kt=1/((1/Kt1)+(1/Kt2)+(1/Kt3)) //total effective stiffness of the torsional system
+Wn=sqrt(Kt/J)//natural freq in rad/sec
+fn=Wn/(2*%pi) //natural freq in Hz
+//output
+mprintf(' The natural frequency of torsional oscillation for the given system is\n %4.4f rad/sec or %4.4f Hz.',Wn,fn)
+mprintf('\nNOTE:Since the value of Kt in the textbook has been rounded of\n   to 3 decimal places,the final answer varies slightly.')
diff --git a/3532/CH2/EX2.3.4/Ex2_6.sce b/3532/CH2/EX2.3.4/Ex2_6.sce
new file mode 100644
index 000000000..c58b1adb1
--- /dev/null
+++ b/3532/CH2/EX2.3.4/Ex2_6.sce
@@ -0,0 +1,19 @@
+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 2.3.4\n')
+//given data
+M=35//mass of flywheel in Kgs
+r=0.3/2 //distance of centre of mass from pivot in m
+T=1.22 //time period of oscillation in sec
+g=9.81//accelaration due to gravity in m/(sec^2)
+//concept is as follows
+//Jo=mass moment of inertia about pivot, Wn=natural freqency
+//thetadd=theta double dot(double differentiation)
+//Jo*thetadd=-M*g*r*theta ....sum of moments is = to zero
+//Jo*thetadd +(M*g*r*theta)=0
+//Wn=sqrt((M*g*r*)/Jo)=2*pi/T
+//calculations
+Jo=M*g*r/((2*%pi/T)^2)
+Jg=Jo-M*r^2 //mass moment of inertia about geometric axis
+//output
+mprintf('Mass moment of inertia about pivot is %4.4f Kg-m^2\n Mass moment of inertia about geometric axis is %4.4f Kg-m^2',Jo,Jg)
diff --git a/3532/CH2/EX2.4.1/Ex2_8.sce b/3532/CH2/EX2.4.1/Ex2_8.sce
new file mode 100644
index 000000000..d05c64876
--- /dev/null
+++ b/3532/CH2/EX2.4.1/Ex2_8.sce
@@ -0,0 +1,18 @@
+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 2.4.1\n')
+//given data
+l=1 //lenght in m
+d=0.005 //dia of rod im m
+D=0.2 //dia of dotor in m
+M=2 //mass of motor in Kg
+G=0.83 *10^11 //modulus of rigidity in N/m^2
+//calculations
+J=M*((D/2)^2)/2 //mass moment of inertia in Kg-m^2
+Ip=(%pi/32)*d^4 //section modulus in m^4
+Kt=G*Ip/l //stiffness in N-m/rad
+Wn=sqrt(Kt/J) //natural freqency in rad/sec
+fn=Wn/(2*%pi) //natural freq in Hz
+//output
+mprintf(' The natural freqency of vibration of torsional pendulum is %4.4f rad/sec\n or %4.4f Hz',Wn,fn)
+mprintf('\nNOTE:In book the natural freqency of vibration of torsional pendulum\nis given as 36 Hz which is wrong.')
diff --git a/3532/CH2/EX2.5.1/Ex2_9.sce b/3532/CH2/EX2.5.1/Ex2_9.sce
new file mode 100644
index 000000000..ffd2b201b
--- /dev/null
+++ b/3532/CH2/EX2.5.1/Ex2_9.sce
@@ -0,0 +1,17 @@
+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 2.5.1\n')
+//given data
+k1=2000 //stiffness of spring 1 in N/m
+k2=1500 //stiffness of spring 2 in N/m
+k3=3000 //stiffness of spring 3 in N/m
+k4=500 //stiffness of spring 4 in N/m
+k5=500 //stiffness of spring 5 in N/m
+fn =10 //natural frequency of system in Hz
+//calculations
+Ke1=1/((1/k1)+(1/k2)+(1/k3)) // effective stiffness of  top 3 springs in series in N/m
+Ke2=k4+k5 // effective stiffness of lower 2 springs in parallel in N/m
+Ke=Ke1+Ke2 //  total effective stiffness of sring system
+M=Ke/(2*%pi*fn)^2 //reqired mass such that the natural frequency of system is 10 Hz  (in Kg)
+//output
+mprintf(' The mass required such that the natural frequency of system is 10 Hz\n is %4.4f Kg',M)
diff --git a/3532/CH2/EX2.5.2/Ex2_10.sce b/3532/CH2/EX2.5.2/Ex2_10.sce
new file mode 100644
index 000000000..26547987e
--- /dev/null
+++ b/3532/CH2/EX2.5.2/Ex2_10.sce
@@ -0,0 +1,22 @@
+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 2.5.2\n')
+//given data
+G=0.83*10^11//rigidity modulus in N/m^2
+J=14.7 //mass moment of inertia in kg-m^2
+l1=0.6 //lenght of section 1 in m
+l2=1.8 //lenght of section 2 in m
+l3=0.25 //lenght of section 3 in m
+d1=0.05 //dia of section 1 in m
+d2=0.08 //dia of section 2 in m
+d3=0.03 //dia of section 3 in m
+//calculations
+Kt1=(G/l1)*(%pi/32)*d1^4 //(%pi/32)*d^4 is the section modulus
+Kt2=(G/l2)*(%pi/32)*d2^4
+Kt3=(G/l3)*(%pi/32)*d3^4
+Kt=1/((1/Kt1)+(1/Kt2)+(1/Kt3)) //total effective stiffness of the torsional system
+Wn=sqrt(Kt/J)//natural freq in rad/sec
+fn=Wn/(2*%pi) //natural freq in Hz
+//output
+mprintf(' The natural frequency of torsional oscillation for the given system is\n %4.4f rad/sec or %4.4f Hz.',Wn,fn)
+mprintf('\nNOTE:Since the value of Kt in the textbook has been rounded of\n   to 3 decimal places,the final answer varies slightly.')
diff --git a/3532/CH2/EX2.6/Ex2_6.sce b/3532/CH2/EX2.6/Ex2_6.sce
new file mode 100644
index 000000000..c58b1adb1
--- /dev/null
+++ b/3532/CH2/EX2.6/Ex2_6.sce
@@ -0,0 +1,19 @@
+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 2.3.4\n')
+//given data
+M=35//mass of flywheel in Kgs
+r=0.3/2 //distance of centre of mass from pivot in m
+T=1.22 //time period of oscillation in sec
+g=9.81//accelaration due to gravity in m/(sec^2)
+//concept is as follows
+//Jo=mass moment of inertia about pivot, Wn=natural freqency
+//thetadd=theta double dot(double differentiation)
+//Jo*thetadd=-M*g*r*theta ....sum of moments is = to zero
+//Jo*thetadd +(M*g*r*theta)=0
+//Wn=sqrt((M*g*r*)/Jo)=2*pi/T
+//calculations
+Jo=M*g*r/((2*%pi/T)^2)
+Jg=Jo-M*r^2 //mass moment of inertia about geometric axis
+//output
+mprintf('Mass moment of inertia about pivot is %4.4f Kg-m^2\n Mass moment of inertia about geometric axis is %4.4f Kg-m^2',Jo,Jg)
diff --git a/3532/CH2/EX2.8/Ex2_8.sce b/3532/CH2/EX2.8/Ex2_8.sce
new file mode 100644
index 000000000..d05c64876
--- /dev/null
+++ b/3532/CH2/EX2.8/Ex2_8.sce
@@ -0,0 +1,18 @@
+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 2.4.1\n')
+//given data
+l=1 //lenght in m
+d=0.005 //dia of rod im m
+D=0.2 //dia of dotor in m
+M=2 //mass of motor in Kg
+G=0.83 *10^11 //modulus of rigidity in N/m^2
+//calculations
+J=M*((D/2)^2)/2 //mass moment of inertia in Kg-m^2
+Ip=(%pi/32)*d^4 //section modulus in m^4
+Kt=G*Ip/l //stiffness in N-m/rad
+Wn=sqrt(Kt/J) //natural freqency in rad/sec
+fn=Wn/(2*%pi) //natural freq in Hz
+//output
+mprintf(' The natural freqency of vibration of torsional pendulum is %4.4f rad/sec\n or %4.4f Hz',Wn,fn)
+mprintf('\nNOTE:In book the natural freqency of vibration of torsional pendulum\nis given as 36 Hz which is wrong.')
diff --git a/3532/CH2/EX2.9/Ex2_9.sce b/3532/CH2/EX2.9/Ex2_9.sce
new file mode 100644
index 000000000..ffd2b201b
--- /dev/null
+++ b/3532/CH2/EX2.9/Ex2_9.sce
@@ -0,0 +1,17 @@
+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 2.5.1\n')
+//given data
+k1=2000 //stiffness of spring 1 in N/m
+k2=1500 //stiffness of spring 2 in N/m
+k3=3000 //stiffness of spring 3 in N/m
+k4=500 //stiffness of spring 4 in N/m
+k5=500 //stiffness of spring 5 in N/m
+fn =10 //natural frequency of system in Hz
+//calculations
+Ke1=1/((1/k1)+(1/k2)+(1/k3)) // effective stiffness of  top 3 springs in series in N/m
+Ke2=k4+k5 // effective stiffness of lower 2 springs in parallel in N/m
+Ke=Ke1+Ke2 //  total effective stiffness of sring system
+M=Ke/(2*%pi*fn)^2 //reqired mass such that the natural frequency of system is 10 Hz  (in Kg)
+//output
+mprintf(' The mass required such that the natural frequency of system is 10 Hz\n is %4.4f Kg',M)