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+//Example 8// Ch 4
+clc;
+clear;
+close;
+// given data
+//current between two parallel plates were 1.22,1.82,2.22 of the initiating photocurrent I1,I2,I3
+x = 1.22;//x is I1/I0 I1=1.22I0
+y = 1.82;//y is I2/I0 I2=1.82I0
+w = 2.22;//z is I3/I0 I3=2.22I0
+d1 = 0.005; //in meters
+d2 = 0.01504; //in meters
+d3 = 0.019; //in meters
+// first ionization coefficients alpha1, alpha2 and alpha3
+alpha1 = log(x)/d1;
+alpha2 = log(y)/d2;
+alpha3 = log(w)/d3;
+printf("first ionization coefficient %f m^-1 \n",alpha1)
+printf("second ionization coefficient %f m^-1 \n",alpha2)
+printf("third ionization coefficient %f m^-1 \n",alpha3)
+// E/p and p were maintained constant so at d3 the secondary ionization coefficient mechanism must be acting without any change in alpha
+z = (w - exp(alpha1*d3))/(w*(exp(alpha1*d3)-1));//secondary ionization coefficient
+printf("secondary ionization coefficient %f \n",z)
+
+