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diff --git a/3472/CH9/EX9.23/Example9_23.sce b/3472/CH9/EX9.23/Example9_23.sce new file mode 100644 index 000000000..163ccdf74 --- /dev/null +++ b/3472/CH9/EX9.23/Example9_23.sce @@ -0,0 +1,38 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 2: CONSTANTS OF OVERHEAD TRANSMISSION LINES
+
+// EXAMPLE : 2.23 :
+// Page number 119
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+d = 0.8/100 // Diameter of conductor(m)
+f = 50.0 // Frequency(Hz)
+D_a_b = 5.0 // Distance between conductors a & b(m)
+D_b_c = 5.0 // Distance between conductors b & c(m)
+D_c_a = 8.0 // Distance between conductors c & a(m)
+l = 25.0 // Length of line(km)
+
+// Calculations
+r = d/2 // Radius of conductor(m)
+e = 8.854*10**-12 // Constant ε_0
+D_e = (D_a_b*D_b_c*D_c_a)**(1.0/3) // Equivalent GMD(m)
+L = 2*((1.0/4)+log(D_e/r))*10**-4 // Inductance(H/km)
+X_L = 2*%pi*f*L // Inductive reactance per km(ohms)
+C = %pi*e/log(D_e/r) // Capacitance(F/m)
+C_l = C*1000.0*l // Capacitance for entire length(F)
+C_lu = C_l*10.0**6 // Capacitance for entire length(μF)
+X_c = 1/(2.0*%pi*f*C_l) // Capacitive reactance to neutral(ohm)
+X_ck = X_c/1000.0 // Capacitive reactance to neutral(kilo-ohm)
+
+// Results
+disp("PART II - EXAMPLE : 2.23 : SOLUTION :-")
+printf("\nInductive reactance of the line per kilometer per phase, X_L = %.3f ohm", X_L)
+printf("\nCapacitance of the line, C = %.3f μF", C_lu)
+printf("\nCapacitive reactance of the transmission line, X_c = %.1f kilo-ohm\n", X_ck)
+printf("\nNOTE: ERROR: Change in obtained answer from that of textbook due to wrong substitution in finding Capacitance")
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