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diff --git a/3472/CH9/EX9.17/Example9_17.sce b/3472/CH9/EX9.17/Example9_17.sce new file mode 100644 index 000000000..28e1d356a --- /dev/null +++ b/3472/CH9/EX9.17/Example9_17.sce @@ -0,0 +1,34 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 2: CONSTANTS OF OVERHEAD TRANSMISSION LINES
+
+// EXAMPLE : 2.17 :
+// Page number 114-115
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+d = 2.0/100 // Diameter of conductor(m)
+D_AB = 4.0 // Spacing between conductor A & B(m)
+D_BC = 4.0 // Spacing between conductor B & C(m)
+D_CA = 8.0 // Spacing between conductor C & A(m)
+
+// Calculations
+r = d/2 // Radius of conductor(m)
+D = 4.0 // Assuming coomon distance(m)
+e = 1.0/(36*%pi)*10**-9 // Constant ε_0
+C_A = 2*%pi*e/(log(D/r)-complex(-0.5,0.866)*log(2))*1000.0 // Capacitance of conductor A(F/km)
+C_Au = C_A*10.0**6 // Capacitance of conductor A(μF/km)
+C_B = 2*%pi*e/log(D/r)*1000.0 // Capacitance of conductor B(F/km)
+C_Bu = C_B*10.0**6 // Capacitance of conductor B(μF/km)
+C_C = 2*%pi*e/(log(D/r)-complex(-0.5,-0.866)*log(2))*1000.0 // Capacitance of conductor C(F/km)
+C_Cu = C_C*10.0**6 // Capacitance of conductor C(μF/km)
+
+// Results
+disp("PART II - EXAMPLE : 2.17 : SOLUTION :-")
+printf("\nCapacitance of conductor A, C_A = (%.5f+%.6fj) μF/km", real(C_Au),imag(C_Au))
+printf("\nCapacitance of conductor B, C_B = %.6f μF/km", C_Bu)
+printf("\nCapacitance of conductor C, C_C = (%.5f%.6fj) μF/km", real(C_Cu),imag(C_Cu))
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