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diff --git a/3472/CH34/EX34.3/Example34_3.sce b/3472/CH34/EX34.3/Example34_3.sce new file mode 100644 index 000000000..32e9d468f --- /dev/null +++ b/3472/CH34/EX34.3/Example34_3.sce @@ -0,0 +1,28 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 8: PROTECTION OF ALTERNATORS AND AC MOTORS
+
+// EXAMPLE : 8.3 :
+// Page number 625
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+kVA = 5000.0 // Alternator rating(kVA)
+V = 6600.0 // Alternator voltage(V)
+X = 2.0 // Synchronous reactance per phase(ohm)
+R = 0.5 // Resistance(ohm)
+ofb = 30.0 // Out-of-balance current(%)
+R_n = 6.5 // Resistance of resistor earthed to star point(ohm)
+
+// Calculations
+I_fl = kVA*1000/(3**0.5*V) // Full load current(A)
+I_ofb = ofb/100*I_fl // Out-of-balance current(A)
+x = R_n/((V/(3**0.5*100*I_ofb))-(R/100)) // Portion of winding unprotected(%)
+
+// Results
+disp("PART III - EXAMPLE : 8.3 : SOLUTION :-")
+printf("\nPortion of alternator winding unprotected, x = %.1f percent", x)
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