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+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 6: CIRCUIT BREAKER
+
+// EXAMPLE : 6.8 :
+// Page number 569
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+kVA = 7500.0    // Rated kVA
+X_st = 9.0      // Sub-transient reactance(%)
+X_t = 15.0      // Transient reactance(%)
+X_d = 100.0     // Direct-axis reactance(%)
+kV = 13.8       // Voltage(kV). Assumption
+
+// Calculations
+kVA_base = 7500.0                       // Base kVA
+kVA_sc_sustained = kVA_base/X_d*100     // Sustained S.C kVA
+I_sc_sustained = kVA_base/(3**0.5*kV)   // Sustained S.C current(A). rms
+I_st = kVA*100/(X_st*3**0.5*kV)         // Initial symmetrical rms current in the breaker(A)
+I_max_dc = 2**0.5*I_st                  // Maximum possible dc component of the short-circuit(A)
+I_moment = 1.6*I_st                     // Momentary current rating of the breaker(A)
+I_interrupt = 1.1*I_st                  // Current to be interrupted by the breaker(A)
+I_kVA = 3**0.5*I_interrupt*kV           // Interrupting kVA
+
+// Results
+disp("PART III - EXAMPLE : 6.8 : SOLUTION :-")
+printf("\nCase(a): Sustained short circuit KVA in the breaker = %.f kVA", kVA_sc_sustained)
+printf("\n         Sustained short circuit current in the breaker = %.1f A (rms)", I_sc_sustained)
+printf("\nCase(b): Initial symmetrical rms current in the breaker = %.f A (rms)", I_st)
+printf("\nCase(c): Maximum possible dc component of the short-circuit in the breaker = %.f A", I_max_dc)
+printf("\nCase(d): Momentary current rating of the breaker = %.f A (rms)", I_moment)
+printf("\nCase(e): Current to be interrupted by the breaker = %.f A (rms)", I_interrupt)
+printf("\nCase(f): Interrupting kVA = %.f kVA \n", I_kVA)
+printf("\nNOTE: Changes in the obtained answer from that of textbook due to more approximation in textbook")