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diff --git a/3472/CH24/EX24.6/Example24_6.sce b/3472/CH24/EX24.6/Example24_6.sce new file mode 100644 index 000000000..c7a194cbc --- /dev/null +++ b/3472/CH24/EX24.6/Example24_6.sce @@ -0,0 +1,35 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 17: ELECTRIC POWER SUPPLY SYSTEMS
+
+// EXAMPLE : 17.6 :
+// Page number 427-428
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+L = 250.0 // Cable length(m)
+P = 80.0*10**3 // Load(W)
+V = 400.0 // Voltage(V)
+PF = 0.8 // Lagging power factor
+time = 4000.0 // Time of operation(hours/annum)
+a = poly(0,'a') // Area of each conductor(Sq.cm)
+cost_instal = 15.0*a+25 // Cost of cable including installation(Rs/m)
+interest_per = 0.1 // Interest & depreciation
+cost_waste_per = 0.1 // Cost of energy wasted(Rs/unit)
+r = 0.173 // Resistance per km of 1 cm^2(ohm)
+
+// Calculations
+I = P/(3**0.5*V*PF) // Line current(A)
+energy_waste = 3.0*I**2*r/a*L*10**-3*time*10**-3 // Energy wasted per annum(kWh)
+cost_energy_waste = cost_waste_per*energy_waste // Annual cost of energy wasted as losses(Rs)
+capitaL_cost_cable = cost_instal*L // Capital cost of cable(Rs)
+annual_cost_cable = capitaL_cost_cable*cost_waste_per // Annual cost on cable(Rs)
+area = (1081.25/375)**0.5 // Area = a(Sq.cm). Simplified and taken final answer
+
+// Results
+disp("PART II - EXAMPLE : 17.6 : SOLUTION :-")
+printf("\nEconomical cross-section of a 3-core distributor cable, a = %.1f cm^2", area)
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