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+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 10: POWER SYSTEM STABILITY
+
+// EXAMPLE : 10.6 :
+// Page number 272
+clear ; clc ; close ; // Clear the work space and console
+funcprot(0)
+
+// Given data
+A = 0.98*exp(%i*0.3*%pi/180) // Constant
+B = 82.5*exp(%i*76.0*%pi/180) // Constant(ohm)
+C = 0.0005*exp(%i*90.0*%pi/180) // Constant(mho)
+D = A // Constant
+V_S = 110.0 // Sending end voltage(kV)
+V_R = 110.0 // Receiving end voltage(kV)
+
+// Calculations
+alpha = phasemag(A) // α(°)
+beta = phasemag(B) // β(°)
+P_max = (V_S*V_R/abs(B))-(abs(A)*V_R**2/abs(B)*cosd((beta-alpha))) // Maximum power transfer(MW)
+B_new = abs(B)*sind(beta) // Constant(ohm)
+beta_new = 90.0 // β(°)
+P_max_new = (V_S*V_R/B_new)-(V_R**2/B_new*cosd(beta_new)) // Maximum power transfer(MW)
+
+// Results
+disp("PART II - EXAMPLE : 10.6 : SOLUTION :-")
+printf("\nSteady state stability limit, P_max = %.2f MW", P_max)
+printf("\nSteady state stability limit if shunt admittance is zero & series resistance neglected, P_max = %.2f MW \n", P_max_new)
+printf("\nNOTE: Changes in the obtained answer from that of textbook is due to precision")