1 files changed, 34 insertions, 0 deletions
diff --git a/3472/CH17/EX17.12/Example17_12.sce b/3472/CH17/EX17.12/Example17_12.sce
new file mode 100644
index 000000000..fac566d53
--- /dev/null
+++ b/3472/CH17/EX17.12/Example17_12.sce
@@ -0,0 +1,34 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 10: POWER SYSTEM STABILITY
+
+// EXAMPLE : 10.12 :
+// Page number 303-304
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+f = 50.0          // Frequency(Hz)
+P = 4.0           // Number of poles
+G = 20.0          // Rating of generator(MVA)
+H = 9.0           // Inertia constant(kWsec/MVA)
+P_m = 26800.0     // Rotational loss(hp)
+P_e = 16000.0     // Electric power developed(kW)
+
+// Calculations
+GH = G*H                                       // Energy stored in rotor at synchronous speed(MJ)
+P_m_kW = P_m*0.746                             // Rotational loss(kW)
+P_a = P_m_kW-P_e                               // Acceleration power(kW)
+P_a1 = P_a/1000.0                              // Acceleration power(MW)
+M = GH/(180*f)                                 // Angular momentum
+acceleration = P_a1/M                          // Acceleration(°/sec^2)
+acceleration_1 = acceleration*%pi/180.0        // Acceleration(rad/sec^2)
+
+// Results
+disp("PART II - EXAMPLE : 10.12 : SOLUTION :-")
+printf("\nKinetic energy stored in the rotor at synchronous speed, GH = %.f MJ", GH)
+printf("\nAcceleration = %.f°/sec^2 = %.2f rad/sec^2 \n", acceleration,acceleration_1)
+printf("\nNOTE: ERROR: H = 9 kW-sec/MVA, not 9 kW-sec/kVA as mentioned in the textbook statement")