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diff --git a/3472/CH10/EX10.18/Example10_18.sce b/3472/CH10/EX10.18/Example10_18.sce new file mode 100644 index 000000000..38bd26961 --- /dev/null +++ b/3472/CH10/EX10.18/Example10_18.sce @@ -0,0 +1,38 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 3: STEADY STATE CHARACTERISTICS AND PERFORMANCE OF TRANSMISSION LINES
+
+// EXAMPLE : 3.18 :
+// Page number 148
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+V_r = 220.0*10**3 // Line voltage at receiving end(V)
+Z = complex(40,200) // Impedance per phasemag(ohm)
+Y = %i*0.0015 // Admittance(mho)
+I_r = 200.0 // Receiving end current(A)
+PF_r = 0.95 // Lagging power factor
+
+// Calculations
+// Case(a)
+A = 1+(Y*Z/2)+((Y*Z)**2/24) // Constant
+B = Z*(1+(Y*Z/6)+((Y*Z)**2/120)+((Y*Z)**3/5040)) // Constant(ohm)
+C = Y*(1+(Y*Z/6)+((Y*Z)**2/120)+((Y*Z)**3/5040)) // Constant(mho)
+D = A // Constant
+E_r = V_r/3**0.5 // Receiving end phasemag voltage(V)
+I_r1 = I_r*exp(%i*-acos(PF_r)) // Line current(A)
+E_s = A*E_r+B*I_r1 // Sending end voltage(V)
+E_s_ll = 3**0.5*E_s/1000.0 // Sending end line voltage(kV)
+// Case(b)
+I_s = C*E_r+D*I_r1 // Sending end current(A)
+
+// Results
+disp("PART II - EXAMPLE : 3.18 : SOLUTION :-")
+printf("\nCase(a): Sending end voltage, E_s = %.1f∠%.2f° kV (line-to-line)", abs(E_s_ll),phasemag(E_s_ll))
+printf("\nCase(b): Sending end current, I_s = %.1f∠%.2f° A\n", abs(I_s),phasemag(I_s))
+printf("\nNOTE: ERROR: Z = (40+j200)Ω, not Z=(60+j200)Ω as given in problem statement")
+printf("\n Changes in obtained answer from that of textbook is due to more precision")
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