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Diffstat (limited to '3446/CH5/EX5.3/Ex5_3.sce')
-rw-r--r-- | 3446/CH5/EX5.3/Ex5_3.sce | 49 |
1 files changed, 49 insertions, 0 deletions
diff --git a/3446/CH5/EX5.3/Ex5_3.sce b/3446/CH5/EX5.3/Ex5_3.sce new file mode 100644 index 000000000..00a87cb1a --- /dev/null +++ b/3446/CH5/EX5.3/Ex5_3.sce @@ -0,0 +1,49 @@ +// Exa 5.3
+// To calculate
+// A) The number of calls per cell site per hour (i.e., call capacity of cell).
+// B) Mean S/I ratio for cell reuse factor equal to 4, 7 and 12.
+
+clc;
+clear all;
+
+VCH=395;//Total voice channels
+CallHT=120;//average call holding time in sec
+Blocking=0.02;// 2%
+PPL=4; //propogation path loss coefficient
+N1=4 //reuse factor
+N2=7; //reuse factor
+N3=12; //reuse factor
+
+//solution
+No_of_VCH1=VCH/N1; //for reuse factor N1
+No_of_VCH2=VCH/N2; //for reuse factor N2
+No_of_VCH3=VCH/N3; //for reuse factor N3
+printf('\nNO of voice channels for N=4 are %d',round(No_of_VCH1));
+printf('\nNO of voice channels for N=7 are %d',round(No_of_VCH2));
+printf('\nNO of voice channels for N=12 are %d\n',round(No_of_VCH3));
+disp("Using the Erlang-B traffic table (see Appendix A) for 99 channels with 2% blocking, we find a traffic load of 87 Erlangs.");
+TrafLoad1=87.004;
+Carryload1=(1-Blocking)*TrafLoad1;
+disp("Using the Erlang-B traffic table (see Appendix A) for 56 channels with 2% blocking, we find a traffic load of 45.88 Erlangs.");
+TrafLoad2=45.877;
+Carryload2=(1-Blocking)*TrafLoad2;
+disp("Using the Erlang-B traffic table (see Appendix A) for 33 channels with 2% blocking, we find a traffic load of 24.6 Erlangs.");
+TrafLoad3=24.629;
+Carryload3=(1-Blocking)*TrafLoad3;
+// To find cell capacity
+Ncall1=Carryload1*3600/CallHT;//Calls per hour per cell
+Ncall2=Carryload2*3600/CallHT;
+Ncall3=Carryload3*3600/CallHT;
+printf('\ncalls per hour per cell for N=4 are %d',round(Ncall1));
+printf('\ncalls per hour per cell for N=7 are %d',round(Ncall2));
+printf('\ncalls per hour per cell for N=12 are %d \n',Ncall3);
+// To find S BY I
+// N=(1/3)[6*(S/I)]^(2/PPL)
+S_I1=10*(PPL/2)*(log10(N1)-log10(1/3)-(2/PPL)*log10(6));//Mean S/I (dB)
+
+S_I2=10*(PPL/2)*(log10(N2)-log10(1/3)-(2/PPL)*log10(6));
+S_I3=10*(PPL/2)*(log10(N3)-log10(1/3)-(2/PPL)*log10(6));
+
+printf('\nMean S/I(dB) for N=4 is %.1f',S_I1);
+printf('\nMean S/I(dB) for N=7 is %.1f',S_I2);
+printf('\nMean S/I(dB) for N=12 is %.1f',S_I3);
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