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-rw-r--r--3428/CH23/EX14.23.21/Ex14_23_21.sce13
1 files changed, 7 insertions, 6 deletions
diff --git a/3428/CH23/EX14.23.21/Ex14_23_21.sce b/3428/CH23/EX14.23.21/Ex14_23_21.sce
index 19726bf37..34102a8e6 100644
--- a/3428/CH23/EX14.23.21/Ex14_23_21.sce
+++ b/3428/CH23/EX14.23.21/Ex14_23_21.sce
@@ -1,12 +1,13 @@
//Section-14,Example-5,Page no.-PC.114
//To calculate the pH of a solution obtained in the given condition.
clc;
-M_1=0.1
-M_2=0.2
-V_1=10
-V_2=40
-V=V_1+V_2
+M_1=0.1 //(M)
+M_2=0.2 //(M)
+V_1=10 //(ml)
+V_2=40 //(ml)
+V=V_1+V_2 //(ml)
m_eq=(M_1*V_1)+(M_2*V_2*2) //mgm. equivalents of [H3O+]
-C_1=m_eq/V //[H3O+]
+C_1=m_eq/V //[H3O+] //(M)
pH=-log10(C_1)
disp(pH,'pH of the given solution')
+//Answer given in the book(pH=4.685) is wrong