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+//Chapter 4, Exmaple 8, page 143
+//Claculate first and secondary ionization coefficient
+clc
+clear
+//(a)first ionization coefficient
+//Using equation 4.7a
+d1 = 0.005
+a1d1 = log(1.22)
+a1 = a1d1/d1
+
+d2 = 0.01504
+a2d2 = log(1.82)
+a2 = a2d2/d2
+
+d3 = 0.019 // wrong value used in the text
+a3d3 = log(2.22)
+a3 = a3d3/d3
+
+printf("\n Alpha 1 = %f m^-1",a1)
+printf("\n Alpha 2 = %f m^-1",a2)
+printf("\n Alpha 3 = %f m^-1",a3)
+printf("\n From the above results we can understand that ionization mechanism must be acting at d3 ")
+
+//secondary ionization coefficient
+I = 2.22
+e = exp(a1*d3)
+Y = (I-e)/(I*(e-1))
+printf("\n secondary ionization coefficient = %f ",Y)
+
+//Answer may vary due to round off error.
+