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+//Chapter 4, Exmaple 10, page 144
+//Claculate (a)Raether's criterion (b)Meek and Lobe's criterion
+clc
+clear
+//(a)Raether's criterion
+// as assumed by Raether and based equation 3.3, 3.50, 4.22 and 4.23
+d = 0.001 // m
+alpha = 10792.2 // m^-1
+p = 101.3 //kPa^-1
+ap = 106.54 // alpha/p Unit: m^-1*kPa^-1
+T = 11253.7 // m^-1*kPa^-1
+B = 273840 // V/m*kPa
+Ep = 58764.81 // E/p Unit:V/m*kPa
+
+ad = 17.7 + log(d)
+E = Ep*p
+Vs = E*d*10^-3 //Voltage breakdown
+printf("\n E = %e V/m",E)
+printf("\n Voltage breakdown = %f kV",Vs)
+
+//(b)Meek and Loeb's criterion
+//Using equation 4.11 and based on 4.24 & 4,25 
+//+ we get Er = 468*10^4 V/m
+Er = 468*10^4 // V/m
+Vs2 = Er*0.001*10^-3
+printf("\n Voltage breakdown = %f kV",Vs2)
+
+// Answers may vary due to round of error