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+// chapter 16
+// example 16.1
+// Determine kVA rating of invertor, Wattage of the rectifier and A-H rating of  battery
+// page-996
+clear;
+clc;
+// given
+Load=600; // in W
+PF=0.8; // (lagging power factor)
+efficiency=80; // in %
+Edc=24; // in V
+backup_time=30; // in min
+// calculate
+// since PF=Load/kVA_rating, therefore we get
+kVA_rating=Load/PF; // calculation of kVA rating of invertor
+wattage=kVA_rating*PF/(efficiency/100); // calculation of Wattage of the rectifier
+Idc=kVA_rating/Edc; // calculation of dc current
+AH_rating=Idc*backup_time/60; // calculation of A-H rating of  battery
+printf("\nThe kVA rating of invertor is \t\t %.2f kW",kVA_rating*1E-3);
+printf("\nThe Wattage of the rectifier is \t %.2f kW",wattage*1E-3);
+printf("\nThe A-H rating of  battery is \t\t %.2f AH",AH_rating);
+// The battery voltage is given as Edc=24 V but the author has  used Edc=48 V. Thats why the answer in the book for AH_rating is wrong.
+\ No newline at end of file