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Diffstat (limited to '3311/CH12/EX12.6/Ex12_6.sce')
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diff --git a/3311/CH12/EX12.6/Ex12_6.sce b/3311/CH12/EX12.6/Ex12_6.sce new file mode 100755 index 000000000..0b39132fc --- /dev/null +++ b/3311/CH12/EX12.6/Ex12_6.sce @@ -0,0 +1,29 @@ +// chapter 12 +// example 12.6 +// Determine values of resonant components Lr and Cr, peak voltage rating of the resonant capacitor and charging and discharging period of capcaitor +// page-785-786 +clear; +clc; +// given +Edc=35; // in V +E0=24; // in V (output voltage) +fr=500; // in KHz +P0=24; // in W +// calculate +fr=fr*1E3; // changing unit from KHz to Hz +// since P0=E0*I0, therefore we get, +I0=P0/E0; // calculation of load current +Zr=Edc/I0; // calculation of load impedance +// since Zr=sqrt(Lr/Cr) and fr=1/(2*%pi*sqrt(Lr*Cr)), multiplying two equations, we get +// Zr*fr=1/(2*%pi*Cr), therefore +Cr=1/(2*%pi*Zr*fr); // calculation of resonant capacitance +Lr=Zr^2*Cr; // calculation of resonant inductance +Vs_p=Edc+I0*Zr; // calculation of peak voltage rating of capacitor +t1=Edc*Cr/I0; // calculation of charging period of capcaitor +t3=sqrt(Lr*Cr)*asin(Edc*sqrt(Cr/Lr)/I0); // calculation of discharging period of capcaitor +printf("\nThe resonant capacitance is \t\t\t Cr=%.4f uF",Cr*1E6); +printf("\nThe resonant inductance is \t\t\t Lr=%.2f uH",Lr*1E6); +printf("\nThe peak voltage rating of capacitor is \t Vs_p=%.f V",Vs_p); +printf("\nThe charging period of capcaitor is \t\t t1=%.3f us",t1*1E6); +printf("\nThe discharging period of capcaitor is \t\t t3=%.3f us",t3*1E6); +// Note :The answer vary slightly due to precise calculation |