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+clc
+// Given that
+hi=10//in mm height of specimen
+ODi=30//in mm outside diameter
+IDi=15//in mm inside diameter
+ODf=38//in mm outside diameter after deformaton
+//Specimen is reduced in thickness by 50%
+hf=(50/100)*hi
+
+// Sample Problem on page no. 886
+
+printf("\n # Determination of Cofficient of Friction # \n")
+
+IDf=sqrt((ODf^2)-((((ODi^2)-(IDi^2))*hi)/hf)) //new internal diameter calculated , by comparing the volume before and after deformation (3.14/4)*(ODi^2-IDi^2)*hi=(3.14/4)*(ODf^2-IDf^2)*hf
+ID=((IDi-IDf)/IDi)*100//change in internal diameter
+
+printf("\n\n With a 50 percent reduction in height and a %d reduction in internal diameter, from the book data Cofficient of Friction = 0.21",ID)
+
+
+
+
+