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+clc 
+// Given that
+to=0.005//in inch depth of cut
+V=400//in ft/min cutting speed
+X=10//in degree rake angle
+w=0.25//in inch width of cut
+tc=0.009//in inch chip thickness
+Fc=125//in lb Cutting force
+Ft=50//in lb thrust force
+
+// Sample Problem on page no. 548
+
+printf("\n # Relative Energies in cutting # \n")
+
+r=to/tc//cutting ratio
+R=sqrt((Ft^2)+(Fc^2))
+B=acosd(Fc/R)+X//friction angle
+F=R*sind(B)
+P=((F*r)/Fc)*100
+printf("\n\n Percentage of total energy going into overcoming friction =%d pecrent",P)
+
+//Answer in the book is approximated to 32 due to approximation in calculation of R and B