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+clc 
+// Given that
+//three metal piece being cast have the same volume but different shapes
+//shapes are sphere,cube,cylinder(height=diameter)
+
+// Sample Problem on page no. 252
+
+printf("\n #solidification time for various shapes# \n")
+
+//solidification time is inversely proportional to the square of surface area
+
+//for sphere
+r=(3/(4*3.14))^(1/3)//radius of the sphere from volume of sphere v=(4*3.14*r^3)/3
+A=4*3.14*((r)^2)
+time1=1/(A)^2
+printf("\n the solidification time for the sphere is %fC",time1)
+
+//for cube
+a=1//edge of the cube
+A=6*a^2
+time2=1/(A)^2
+printf("\n the solidification time for the cube is %fC",time2)
+
+//for cylinder
+//given height =diameter 
+//radius=2*height
+r=(1/(2*3.14))^(1/3)//radius of the cylinder from volume of the cylinder v=3.14*r^2*h
+A=(6*3.14*(r^2)) //area of the cylinder = (2*3.14*radius^2) + (2*3.14*radius*height)
+time3=1/(A)^2
+printf("\n the solidification time for the sphere is %fC",time3)