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Diffstat (limited to '3204/CH9/EX9.2/Ex9_2.sce')
| -rw-r--r-- | 3204/CH9/EX9.2/Ex9_2.sce | 19 |
1 files changed, 19 insertions, 0 deletions
diff --git a/3204/CH9/EX9.2/Ex9_2.sce b/3204/CH9/EX9.2/Ex9_2.sce new file mode 100644 index 000000000..dac26bcfa --- /dev/null +++ b/3204/CH9/EX9.2/Ex9_2.sce @@ -0,0 +1,19 @@ +// Initilization of variables
+W1=2000 //N (or 2 kN)// load at joint D of the truss
+W2=4000 //N (or 4 kN)// load at joint E of the truss
+Lac=6 //m // length of the tie
+Lab=3 //m
+Lbc=3 //m
+theta=60 //degree // interior angles of the truss
+// Calculations
+// Here A is simply supported & B is roller support. Now the SUPPORT REACTIONS are given as,
+Rc=((W1*(Lab/2))+(W2*(Lab+(Lbc/2))))/Lac //N // Taking moment at A
+Ra=W1+W2-Rc //N // Take sum Fy=0
+// Calculations
+// Calculating the axial forces in the respective members by METHOD OF SECTION
+// A section is drawn passing through member DE such that it cuts the respective member. Now consider the equilibrium of the left hand portion of the truss. The three unknown forces are Fde, Fdb, & Fab
+// Take moment about B
+Fde=((3*Ra)-(W1*Lab*sind(30)))/(3*cosd(30)) //N // (T)
+// Results
+clc
+printf('The axial force in the member DE (Fde)is %f N \n',Fde)
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