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-rw-r--r--3204/CH5/EX5.2/Ex5_2.sce14
-rw-r--r--3204/CH5/EX5.3/Ex5_3.sce20
-rw-r--r--3204/CH5/EX5.4/Ex5_4.sce17
-rw-r--r--3204/CH5/EX5.5/Ex5_5.sce16
-rw-r--r--3204/CH5/EX5.6/Ex5_6.sce18
5 files changed, 85 insertions, 0 deletions
diff --git a/3204/CH5/EX5.2/Ex5_2.sce b/3204/CH5/EX5.2/Ex5_2.sce
new file mode 100644
index 000000000..921cdc9d8
--- /dev/null
+++ b/3204/CH5/EX5.2/Ex5_2.sce
@@ -0,0 +1,14 @@
+//Inilization of variables
+W=2000 //N
+Lab=2 //m //length of the member from the vertical to the 1st load of 2000 N
+Lac=5 //m //length of the member from the vertical to the 2nd load of 2000 N
+Lpq=3.5 //m
+//Calculations
+Rq=((W*Lab)+(W*Lac))/Lpq //N //take moment abt. pt P
+Xp=Rq //N //sum Fx=0
+Yp=2*W //N //sum Fy=0
+Rp=sqrt(Xp^2+Yp^2) //N
+//Resuts
+clc
+printf('The reaction at P is %f N \n',Rp)
+printf('The reaction at Q is %f N \n',Rq)
diff --git a/3204/CH5/EX5.3/Ex5_3.sce b/3204/CH5/EX5.3/Ex5_3.sce
new file mode 100644
index 000000000..780c792c3
--- /dev/null
+++ b/3204/CH5/EX5.3/Ex5_3.sce
@@ -0,0 +1,20 @@
+//Initilization of vaiables
+W=25 //N // self weight of the ladder
+M=75 //N // weight of the man standing o the ladder
+theta=63.43 //degree // angle which the ladder makes with the horizontal
+alpha=30 //degree // angle made by the string with the horizontal
+Loa=2 //m // spacing between the wall and the ladder
+Lob=4 //m //length from the horizontal to the top of the ladder touching the wall(vertical)
+//Calculations
+//Using matrix to solve the simultaneous eqn's 3 & 4
+A=[2 -4;1 -0.577]
+B=[100;100]
+C=inv(A)*B
+//Results
+clc
+printf('The reaction at A i.e Ra is %f N \n',C(1))
+printf('The reaction at B i.e Rb is %f N \n',C(2))
+//Calculations
+T=C(2)/cosd(alpha) //N // from (eqn 1)
+//Results
+printf('The required tension in the string is %f N \n',T)
diff --git a/3204/CH5/EX5.4/Ex5_4.sce b/3204/CH5/EX5.4/Ex5_4.sce
new file mode 100644
index 000000000..6624e8ed5
--- /dev/null
+++ b/3204/CH5/EX5.4/Ex5_4.sce
@@ -0,0 +1,17 @@
+//Initilization of variables
+W=100 //N
+theta=60 //degree //angle made by the ladder with the horizontal
+alpha=30 //degree //angle made by the ladder with the vertical wall
+Lob=4 //m // length from the horizontal to the top of the ladder touching the wall(vertical)
+Lcd=2 //m // length from the horizontal to the centre of the ladder where the man stands
+//Calculations
+Lab=Lob*secd(alpha) //m //length of the ladder
+Lad=Lcd*tand(alpha) //m
+Rb=(W*Lad)/Lab //N //take moment at A
+Xa=Rb*sind(theta) //N // From eq'n 1
+Ya=W+Rb*cosd(theta) //N From eq'n 2
+//Results
+clc
+printf('The reaction at B i.e Rb is %f N \n',Rb)
+printf('The horizontal reaction at A i.e Xa is %f N \n',Xa)
+printf('The vertical reaction at A i.e Ya is %f N \n',Ya)
diff --git a/3204/CH5/EX5.5/Ex5_5.sce b/3204/CH5/EX5.5/Ex5_5.sce
new file mode 100644
index 000000000..b1297171f
--- /dev/null
+++ b/3204/CH5/EX5.5/Ex5_5.sce
@@ -0,0 +1,16 @@
+//Initilization of variables
+W=100 //N //self weight of the man
+alpha=30 //degree // angle made by the ladder with the wall
+Lob=4 //m // length from the horizontal to the top of the ladder touching the wall(vertical)
+Lcd=2 //m
+//Calculations
+// using the equiblirium equations
+Ya=W //N // From eq'n 2
+Lad=Lcd*tand(alpha) //m //Lad is the distance fom pt A to the point where the line from the cg intersects the horizontal
+Rb=(W*Lad)/Lob //N // Taking sum of moment abt A
+Xa=Rb //N // From eq'n 1
+//Results
+clc
+printf('The horizontal reaction at A i.e Xa is %f N \n',Xa)
+printf('The vertical reaction at A i.e Ya is %f N \n',Ya)
+printf('The reaction at B i.e Rb is %f N \n',Rb)
diff --git a/3204/CH5/EX5.6/Ex5_6.sce b/3204/CH5/EX5.6/Ex5_6.sce
new file mode 100644
index 000000000..dbe1e5ba2
--- /dev/null
+++ b/3204/CH5/EX5.6/Ex5_6.sce
@@ -0,0 +1,18 @@
+//Initilization of variables
+d=0.09 //m //diametre of the right circular cylinder
+h=0.12 //m //height of the cyinder
+W=10 //N // self weight of the bar
+l=0.24 //m //length of the bar
+//Calculations
+theta=atand(h/d) // angle which the bar makes with the horizontal
+Lad=sqrt(d^2+h^2) //m // Lad is the length of the bar from point A to point B
+Rd=(W*h*cosd(theta))/Lad //N // Taking moment at A
+Xa=Rd*sind(theta) //N // sum Fx=0.... From eq'n 1
+Ya=W-(Rd*cosd(theta)) //N // sum Fy=0..... From eq'n 2
+Ra=sqrt(Xa^2+Ya^2) //resultant of Xa & Ya
+//Results
+clc
+printf('The horizontal reaction at A i.e Xa is %f N \n',Xa)
+printf('The vertical reaction at A i.e Ya is %f N \n',Ya)
+printf('Therefore the reaction at A i.e Ra is %f N \n',Ra)
+printf('The reaction at D i.e Rd is %f N \n',Rd)