diff options
Diffstat (limited to '3204/CH14/EX14.7/Ex14_7.sce')
| -rw-r--r-- | 3204/CH14/EX14.7/Ex14_7.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/3204/CH14/EX14.7/Ex14_7.sce b/3204/CH14/EX14.7/Ex14_7.sce new file mode 100644 index 000000000..5092b6be2 --- /dev/null +++ b/3204/CH14/EX14.7/Ex14_7.sce @@ -0,0 +1,22 @@ +// Intilization of variables
+acc=0.5 // m/s^2 // acceleration of the elevator
+s=25 // m // distance travelled by the elevator from the top
+u=0 // m/s
+g=9.81 // m/s^2 // acc due to gravity
+// Calculations
+// Using eq'n the eq'n v^2-u^2=2*a*s, solving for v we get,
+v=sqrt((2*acc*s)+(u^2)) // m/s
+// Now solving eq'n 1 & 2 for t we get, (4.655*t^2)-(5*t)+(25)=0
+// Find the roots of the eq'n using the eq'n,t=(-b+sqrt(b^2-(4*a*c)))/(2*a).In this eq'n the values of a,b & c are,
+a=4.655
+b=-5
+c=-25
+t=(-b+sqrt((b^2)-(4*a*c)))/(2*a) // seconds
+// Let S_1 be the distance travelled by the elevator after it travels 25 m from top when the stone hits the elevator,This disance S_1 is given as,
+S_1=(v*t)+((1/2)*acc*t^2) // m
+// Let S be the total dist from top when the stone hits the elevator,
+S=S_1+s // m
+// Results
+clc
+printf('The time taken by the stone to hit the elevator is %f seconds \n',t)
+printf('The distance (S)travelled by the elevator at the time of impact is %f m \n',S)
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