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diff --git a/317/CH8/EX8.3/example3.sce b/317/CH8/EX8.3/example3.sce
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+// find emitter current 
+// Electronic Principles
+// By Albert Malvino , David Bates
+// Seventh Edition
+// The McGraw-Hill Companies
+// Example 8-3, page 266
+
+clear;clc; close;
+
+// Given data
+R1=10*10^3;// in ohms
+R2=2.2*10^3;// in ohms
+Rc=3.6*10^3;// in ohms
+Re=1*10^3;// in ohms
+Bdc=200;// current gain
+Vbb=1.8;// base supply voltage in volts 
+Vbe=0.7;// voltage across emitter in volts
+
+// Calculations
+Rth=(R1*R2)/(R1+R2);// thevenin voltage in volts(R1||R2)
+Rin=Bdc*Re;// input resistance of base
+// as Rth<0.01*Rin, voltage divider is stiff
+Ie=(Vbb-Vbe)/(Re+(Rth/Bdc));// emitter current in amperes
+disp("Amperes",Ie,"Emitter Current")
+
+// Result
+// voltage divider is stiff, emitter current is 1.09 milliamperes
diff --git a/317/CH8/EX8.3/example3.txt b/317/CH8/EX8.3/example3.txt
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+voltage divider is stiff, emitter current is 1.09 milliamperes