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+// find current through the resistor
+// Electronic Principles
+// By Albert Malvino , David Bates
+// Seventh Edition
+// The McGraw-Hill Companies
+// Example 15-8, page 546
+
+clear; clc; close;
+
+// Given data
+R1=82;// givenin ohms
+R2=22;// given in ohms
+Vgt=75;//  in volts
+
+// Calculations
+// Ideally the triac has 0 voltas across it when conducting 
+I=Vgt/R2;// current through 22 ohm resistor in amperes
+disp("Amperes",I,"current through 22 ohm resistor=")
+
+// Results
+// Current through the 22 ohm resistor is 3.41 Amperes
+\ No newline at end of file
diff --git a/317/CH15/EX15.8/example8.txt b/317/CH15/EX15.8/example8.txt
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+Current through the 22 ohm resistor is 3.41 Amperes
+\ No newline at end of file