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diff --git a/3161/CH6/EX6.4/Ex6_4.sce b/3161/CH6/EX6.4/Ex6_4.sce
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+clc;
+//page 365
+//problem 6.4
+
+//Given energy per bit Eb = 0.01
+Eb = 0.01;
+
+//Given fundamental frequency is fb = 8 KHz 
+fb = 8*10^3;
+
+//No of symbols M = 16
+M = 16;
+
+N = log2(M);
+
+BW_BPSK = 2*fb;
+disp('Bandwidth for BPSK is '+string(BW_BPSK)+'Hz');
+
+BW_QPSK = fb;
+disp('Bandwidth for QPSK is '+string(BW_QPSK)+'Hz');
+
+BW_16MPSK = fb/2;
+disp('Bandwidth for 16 MPSK is '+string(BW_16MPSK)+'Hz');
+
+BW_BFSK = 4*fb;
+disp('Bandwidth for BFSK is '+string(BW_BFSK)+'Hz');
+
+BW_MSK = 1.5*fb;
+disp('Bandwidth for MSK is '+string(BW_MSK)+'Hz');
+
+BW_16MFSK = 2*M*fb;
+disp('Bandwidth for 16 MFSK is '+string(BW_16MFSK)+'Hz');
+
+
+Min_dist_BPSK = 2*(Eb)^0.5;
+disp('Minimum distance in signal space in BPSK is '+string(Min_dist_BPSK));
+
+Min_dist_QPSK = 2*(Eb)^0.5;
+disp('Minimum distance in signal space in QPSK is '+string(Min_dist_QPSK));
+
+//The given answer in the textbook is 0.0152, which appears to be wrong. The correct answer is 0.078
+Min_dist_16MPSK = (4*N*Eb*(sin(%pi/16))^2)^0.5;
+disp('Minimum distance in signal space in 16 MPSK is '+string(Min_dist_16MPSK));
+
+Min_dist_BFSK = (2*Eb)^0.5;
+disp('Minimum distance in signal space in ortho BFSK is '+string(Min_dist_BFSK));
+
+Min_dist_MSK = 2*(Eb)^0.5;
+disp('Minimum distance in signal space in MSK is '+string(Min_dist_MSK));
+
+Min_dist_16MFSK = (2*N*Eb)^0.5;
+disp('Minimum distance in signal space in ortho 16 MFSK is '+string(Min_dist_16MFSK));
+
+disp('The best method that provides least noise susceptibility is 16 MFSK, then BPSK, then QPSK, then comes MSK, then orthogonal BFSK and finally 16 MPSK')
+
+